6y^2-2y+10=14

Solution for 6y^2-2y+10=14 equation:

6y^2-2y+10=14

We move all terms to the left:

6y^2-2y+10-(14)=0

We add all the numbers together, and all the variables

6y^2-2y-4=0

a = 6; b = -2; c = -4;
Δ = b2-4ac
Δ = -22-4·6·(-4)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-10}{2*6}=\frac{-8}{12}
=-2/3
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+10}{2*6}=\frac{12}{12}
=1
$